Java
2016-11-04 15:38:09.395974+01 by Dan Lyke 0 comments
Java. Where "byte" is signed, so "b == 0xfe" is always false, but "(b & 0xff) == 0xfe" can be true.
2016-11-04 15:38:09.395974+01 by Dan Lyke 0 comments
Java. Where "byte" is signed, so "b == 0xfe" is always false, but "(b & 0xff) == 0xfe" can be true.
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